**Problem:**

**Reference: Problem Primer for the Olympiad by C. R. Pranesachar, et al. Prism Books**

**Amazon India link: **https://www.amazon.in/Problem-Primer-Olympiad-2Ed-Pranesachar/dp/8172862059/ref=sr_1_2?s=books&ie=UTF8&qid=1518894790&sr=1-2&keywords=problem+primer+for+the+olympiad

Five men A, B, C, D, E are wearing caps of black or white colour without each knowing the colour of his own cap. It is known that a man wearing a black cap always speaks the truth while a man wearing a white cap always lies. If they make the following statements, find the colour of the cap worn by each of them:

A: I see three black and one white cap.

B: I see four white caps.

C: I see one black and three white caps.

D: I see four black caps.

**Solution:**

**Suppose E is wearing a white cap:**

Then, D is lying and hence must be wearing a white cap. Since D and E both have white caps, A is lying and hence, he must be wearing white cap.** If C is speaking truth, then C must be wearing a black cap **and B must be wearing a black cap as observed by C. **But, then B must observe a black cap on C. Hence, B must be lying. This implies that B is wearing a white cap which is a contradiction to C’s statement.**

* On the other hand, if C is lying, *then C must be wearing a white cap. Thus, A, C, D and E are wearing white caps which makes B’s statement true. But, then B must be wearing a black cap and this makes C statement correct.

Thus, *E must be wearing a black cap.* This implies that B is lying and hence, must be having a white cap. But, then D is lying and hence, must be having a white cap since B and D have white caps. A is not saying the truth. Hence, A must be wearing a white cap. These together imply that C is truthful. Hence, C must be wearing a black cap. Thus, we have the following distribution:

A: white cap; B: white cap; C: black cap; D: white cap; E: black cap.

**Hope you enjoyed it! There can be some other approaches too starting with some other assumption(s).**

*Nalin Pithwa.*