This is one of the prime utilities of trigonometry —- to calculate heights and distances, called as surveying in civil engineering.

**1. **From the extremities of a horizontal base line AB, whose length is 1 km, the bearings of the foot C of a tower are observed and it is found that is 56 degrees and 23 minutes and is 47 degrees and 15 minutes, and the elevation of the tower from A is 9 degrees and 25 minutes, find the height of the tower.

**2. **A man in a balloon observes that the angle of depression of an object on the ground bearing due north is 33 degrees; the balloon drifts 3 km due west and the angle of depression is now found to be 21 degrees. Find the height of the balloon.

**3. **A tower PN stands on level ground. A base AB is measured at right angles to AN, the points A, B, and N being in the same horizontal plane, and the angles PAN and PBN are found to be and respectively. Prove that the height of the tower is

AB

If AB is 100m, degrees and degrees, calculate the height.

**4. **At each end of a horizontal base of length 2a, it is found that the angular height of a certain peak is and that at the middle point it is . Prove that the vertical height of the peak is

**5. **To find the distance from A to P, a distance AB of 1 km. is measured for a convenient direction. At A the angle PAB is found to be 41 degrees 18 min and at B, the angle PBA is found to be 114 degrees and 38 min. What is the required distance to the nearest metre?

More later,

Nalin Pithwa

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4th one, please

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Hello: Yes, there is something “fishy” about this question. I am getting some weird answers, as well as some sensible answers. I have yet to churn more. Let me get back to you in a couple of days. Thanks for the comment/observation, though. Regards, NP

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